C++实现：判断输入整数总和是否为质数

```cpp #include <iostream> using namespace std; // 判断一个数是否为质数 bool isPrime(int num) { if (num < 2) return false; for (int i = 2; i * i <= num; i++) { if (num % i == 0) return false; } return true; } int main() { int n; cin >> n; int sum = 0; for (int i = 0; i < n; i++) { int num; cin >> num; sum += num; } if (isPrime(sum)) { cout << "prime" << endl; } else { cout << "not prime" << endl; } return 0; } ``` ######[AI问答 | 192点数解答 | 2025-11-22 20:12:07]