C++：巨龙交替喷火，求解热量超20的石块编号

```cpp #include <iostream> using namespace std; int main() { int n; cin >> n; int heat1 = 0, heat2 = 0; for (int i = 0; i < n; i++) { int heat; cin >> heat; if (i % 2 == 0) { heat1 += heat; } else { heat2 += heat; } } if (heat1 > 20) { cout << 1 << endl; } if (heat2 > 20) { cout << 2 << endl; } return 0; } ``` ######[AI问答 | 167点数解答 | 2025-11-22 19:11:12]