10×10网格追击：梁总追捕双牛，代码逻辑暗藏哪些玄机？

```python # 定义方向，0: 北，1: 东，2: 南，3: 西 directions = [(-1, 0), (0, 1), (1, 0), (0, -1)] # 读取地图 map_grid = [] for _ in range(10): row = input() map_grid.append(row) # 寻找梁总和牛的初始位置 for i in range(10): for j in range(10): if map_grid[i][j] == 'F': farmer_x, farmer_y = i, j elif map_grid[i][j] == 'C': cows_x, cows_y = i, j # 初始方向都为北 farmer_direction = 0 cows_direction = 0 # 记录状态，避免无限循环 visited = set() # 初始化时间 minutes = 0 while True: # 记录当前状态 state = (farmer_x, farmer_y, farmer_direction, cows_x, cows_y, cows_direction) if state in visited: print(0) break visited.add(state) # 梁总移动 new_farmer_x = farmer_x + directions[farmer_direction][0] new_farmer_y = farmer_y + directions[farmer_direction][1] if 0 <= new_farmer_x < 10 and 0 <= new_farmer_y < 10 and map_grid[new_farmer_x][new_farmer_y] != '*': farmer_x = new_farmer_x farmer_y = new_farmer_y else: farmer_direction = (farmer_direction + 1) % 4 # 牛移动 new_cows_x = cows_x + directions[cows_direction][0] new_cows_y = cows_y + directions[cows_direction][1] if 0 <= new_cows_x < 10 and 0 <= new_cows_y < 10 and map_grid[new_cows_x][new_cows_y] != '*': cows_x = new_cows_x cows_y = new_cows_y else: cows_direction = (cows_direction + 1) % 4 # 判断是否相遇 minutes += 1 if farmer_x == cows_x and farmer_y == cows_y: print(minutes) break ``` 我在以往的开发过程中，碰到过以下几点需要格外小心处理的地方： 1. 边界条件判断，要确保梁总和牛不会移动到地图之外。 2. 状态记录，避免因为循环导致程序陷入无限循环。 3. 移动和转向逻辑，确保梁总和牛的移动和转向规则正确。 ######[AI写代码神器 | 647点数解答 | 2025-11-21 18:19:23]