C++程序：破解水晶花园门上密码锁的奥秘

```cpp #include <iostream> using namespace std; int main() { int n; cin >> n; // 标记因数 bool isFactor[n + 1] = {false}; for (int i = 1; i <= n; i++) { if (n % i == 0) { isFactor[i] = true; } } // 输出非因数 bool first = true; for (int i = 1; i <= n; i++) { if (!isFactor[i]) { if (!first) { cout << " "; } cout << i; first = false; } } cout << endl; return 0; } ``` ######[AI问答 | 182点数解答 | 2025-11-01 19:09:27]