C++实现：输入整数判断是否为质数，输出“prime”或“not prime”

```cpp #include <iostream> using namespace std; int main() { int n; cin >> n; bool isPrime = true; for (int i = 2; i * i <= n; i++) { if (n % i == 0) { isPrime = false; break; } } if (isPrime) { cout << "prime" << endl; } else { cout << "not prime" << endl; } return 0; } ``` ######[AI问答 | 131点数解答 | 2025-10-25 19:24:46]