C++：根据输入整数奇偶输出 1 到指定范围数字的代码实现

```cpp #include <iostream> using namespace std; int main() { int x, y, z; cin >> x >> y >> z; if (x % 2 == 1) { for (int i = 1; i <= y; i++) { cout << i << " "; } } else { for (int i = 1; i <= z; i++) { cout << i << " "; } } return 0; } ``` ######[AI问答 | 109点数解答 | 2025-10-02 21:28:39]