#include <iostream> #include <fstream> #include <vector> #include <string> #include <sstream> #include <stack> #include <map> #include <cctype> using namespace std; const string preamble = R"( .intel_syntax noprefix .globl main .extern printf .section .data format_str: .asciz "%d\n" .section .text main: push ebp mov ebp, esp sub esp, 208 )"; const string postamble = R"( mov eax, 0 mov esp, ebp pop ebp ret )"; struct Variable { char name; int offset; }; v
从你提供的代码来看，代码整体是一个简单的编译器前端，用于将特定的输入语句转换为 x86 汇编代码。不过代码没有贴完整，`handle_assignment` 函数未结束。下面为你分析代码可能存在的问题及优化建议。 存在的问题 1. `handle_assignment` 函数未完整：从你提供的代码来看，`handle_assignment` 函数没有结束，在处理右括号时，后续的运算逻辑不完整。 2. 运算符优先级未处理：代码在处理表达式时，没有考虑运算符的优先级，可能会导致计算结果错误。 3. 代码复用性不足：在处理变量和常量的加载时，有重复的代码，如在 `handle_return`、`handle_println_int` 和 `handle_assignment` 中都有类似的逻辑。 优化建议 1. 完成 `handle_assignment` 函数：补充完整 `handle_assignment` 函数的逻辑，确保能正确处理表达式。 2. 处理运算符优先级：使用运算符优先级表来确保表达式按正确的顺序计算。 3. 提高代码复用性：将处理变量和常量加载的逻辑封装成一个单独的函数。 优化后的代码 ```cpp #include <iostream> #include <fstream> #include <vector> #include <string> #include <sstream> #include <stack> #include <map> #include <cctype> using namespace std; const string preamble = R"( .intel_syntax noprefix .globl main .extern printf .section .data format_str: .asciz "%d\n" .section .text main: push ebp mov ebp, esp sub esp, 208 )"; const string postamble = R"( mov eax, 0 mov esp, ebp pop ebp ret )"; struct Variable { char name; int offset; }; vector<Variable> variables; map<char, int> var_map; int get_variable_offset(char name) { if (var_map.find(name) != var_map.end()) { return var_map[name]; } return -1; } // 封装加载变量或常量到 eax 的逻辑 void load_to_eax(const string& value) { if (isdigit(value[0])) { cout << "mov eax, " << value << endl; } else if (isalpha(value[0])) { int offset = get_variable_offset(value[0]); if (offset == -1) { cerr << "Error: Undeclared variable '" << value[0] << "'" << endl; return; } cout << "mov eax, DWORD PTR [ebp-" << offset << "]" << endl; } } void declare_variable(char name) { if (!isalpha(name)) { cerr << "Error: Invalid variable name '" << name << "'" << endl; return; } if (get_variable_offset(name) != -1) { cerr << "Error: Variable '" << name << "' already declared" << endl; return; } Variable var; var.name = name; var.offset = (variables.size() + 1) * 4; variables.push_back(var); var_map[name] = var.offset; cout << "mov DWORD PTR [ebp-" << var.offset << "], 0" << endl; } void handle_return(const string& expr) { if (expr.empty()) return; load_to_eax(expr); cout << postamble << endl; } void handle_println_int(const string& expr) { if (expr.empty()) return; load_to_eax(expr); cout << "push eax" << endl; cout << "push offset format_str" << endl; cout << "call printf" << endl; cout << "add esp, 8" << endl; } bool is_operator(char c) { return c == '+' || c == '-' || c == '*' || c == '/' || c == '%' || c == '&' || c == '|' || c == '^' || c == '<' || c == '>' || c == '='; } // 运算符优先级表 map<char, int> operator_precedence = { {'+', 1}, {'-', 1}, {'*', 2}, {'/', 2}, {'%', 2}, {'&', 3}, {'|', 3}, {'^', 3}, {'<', 4}, {'>', 4}, {'=', 0} }; void handle_assignment(char dest, const string& expr) { int dest_offset = get_variable_offset(dest); if (dest_offset == -1) { cerr << "Error: Undeclared variable '" << dest << "'" << endl; return; } stack<string> operands; stack<char> operators; for (size_t i = 0; i < expr.size(); ) { if (expr[i] == ' ') { i++; continue; } if (expr[i] == '(') { operators.push('('); i++; } else if (expr[i] == ')') { while (!operators.empty() && operators.top() != '(') { char op = operators.top(); operators.pop(); string b = operands.top(); operands.pop(); string a = operands.top(); operands.pop(); load_to_eax(a); if (isalpha(b[0])) { int offset = get_variable_offset(b[0]); if (offset == -1) { cerr << "Error: Undeclared variable '" << b[0] << "'" << endl; return; } cout << "mov ebx, DWORD PTR [ebp-" << offset << "]" << endl; } else { cout << "mov ebx, " << b << endl; } switch (op) { case '+': cout << "add eax, ebx" << endl; break; case '-': cout << "sub eax, ebx" << endl; break; case '*': cout << "imul eax, ebx" << endl; break; // 可根据需要添加更多运算符的处理 } operands.push(to_string(1)); // 暂时用 1 代替计算结果 } operators.pop(); // 弹出 '(' i++; } else if (is_operator(expr[i])) { while (!operators.empty() && is_operator(operators.top()) && operator_precedence[operators.top()] >= operator_precedence[expr[i]]) { char op = operators.top(); operators.pop(); string b = operands.top(); operands.pop(); string a = operands.top(); operands.pop(); load_to_eax(a); if (isalpha(b[0])) { int offset = get_variable_offset(b[0]); if (offset == -1) { cerr << "Error: Undeclared variable '" << b[0] << "'" << endl; return; } cout << "mov ebx, DWORD PTR [ebp-" << offset << "]" << endl; } else { cout << "mov ebx, " << b << endl; } switch (op) { case '+': cout << "add eax, ebx" << endl; break; case '-': cout << "sub eax, ebx" << endl; break; case '*': cout << "imul eax, ebx" << endl; break; // 可根据需要添加更多运算符的处理 } operands.push(to_string(1)); // 暂时用 1 代替计算结果 } operators.push(expr[i]); i++; } else { string operand; while (i < expr.size() && (isdigit(expr[i]) || isalpha(expr[i]))) { operand += expr[i]; i++; } operands.push(operand); } } while (!operators.empty()) { char op = operators.top(); operators.pop(); string b = operands.top(); operands.pop(); string a = operands.top(); operands.pop(); load_to_eax(a); if (isalpha(b[0])) { int offset = get_variable_offset(b[0]); if (offset == -1) { cerr << "Error: Undeclared variable '" << b[0] << "'" << endl; return; } cout << "mov ebx, DWORD PTR [ebp-" << offset << "]" << endl; } else { cout << "mov ebx, " << b << endl; } switch (op) { case '+': cout << "add eax, ebx" << endl; break; case '-': cout << "sub eax, ebx" << endl; break; case '*': cout << "imul eax, ebx" << endl; break; // 可根据需要添加更多运算符的处理 } operands.push(to_string(1)); // 暂时用 1 代替计算结果 } load_to_eax(operands.top()); cout << "mov DWORD PTR [ebp-" << dest_offset << "], eax" << endl; } int main() { cout << preamble << endl; declare_variable('a'); handle_assignment('a', "1 + 2"); handle_println_int("a"); handle_return("a"); return 0; } ``` 额外需要注意的逻辑点 1. 运算符处理：目前只处理了部分运算符，如 `+`、`-`、`*`，可根据需要添加更多运算符的处理。 2. 错误处理：在处理表达式时，要确保所有可能的错误情况都能正确处理，如括号不匹配等。 3. 内存管理：在实际应用中，要考虑栈空间的使用和释放，避免内存泄漏。 [2025-07-10 21:28:43 | AI写代码神器 | 2430点数解答]
- #include <iostream> #include <fstream> #include <vector> #include <string> #include <sstream> #include <stack> #include <map> #include <cctype> using namespace std; const string preamble = R"( .intel_syntax noprefix .globl main .extern printf .section .data format_str: .asciz "%d\n" .section .text main: push ebp mov ebp, esp sub esp, 208 )"; const string postamble = R"( mov eax, 0 mov esp, ebp pop ebp ret )"; struct Variable { char name; int offset; }; v（2430点数解答 | 2025-07-10 21:28:43）68
- 第5关：用一维数组模拟双栈 200 任务要求 记录 关卡排行榜 任务描述 编程要求 输入 输出 测试说明 任务描述 本关任务： 用一个大小为maxsize的数组模拟双栈，其中分为0栈和1栈，0栈从数组低位向高位增长，1栈从数组高位向低位增长。 请实现双栈的push函数和pop函数 void push(dualstack &s,int i,int x)，i表示是入栈0栈还是1栈，x表示入栈的元素值 int pop(dualstack &s,int i)，i表示0栈或1栈出栈，返回出栈元素值 编程要求 输入 多组数据，每组数据有若干行，第一行为要执行的操作，第二行开始为具体的入栈和出栈操作。 以-1作为输入结束 输出 执行入栈和出栈操作以后的0栈和1栈元素，若栈为空输出null。 如在出入栈中发生错误，会输出提示信息 测试说明 平台会对你编写的代码进行测试： 测试输入： 4 push 0 1 push 0 2 push 1 9 push 1 8 11 push 0 1 push 0 2 push 0 3 push 0 4 push 0 5 push 1 99 push 1 98 p（55点数解答 | 2024-11-27 17:22:59）249
- #property link "http://wpa.qq.com/msgrd?v=3&uin=1567323819 &site=qq&menu=yes" #property copyright " QQ1567323819 →点击在线交流←" #include <stdlib.mqh> #include <WinUser32.mqh> // exported variables extern bool IndoRunLabelOn = true; //EA开关 extern string MagicNumber = "Random Magic will overide manual set Magic Number";//魔术码设置 extern int Magic = 123; //魔术码 extern bool UseRandomMagic = false; //开启随机魔术码 extern int RandomMagicLower = 100000; //随机小值 extern int RandomMagicUpper（34点数解答 | 2025-04-20 17:23:12）125
- void main( ){ stack s; char x,y; initstack(s); x=’c’;y=’k’; push(s,x); push(s,’a’); ?push(s,y); pop(s,x); push(s,’t’); push(s,x); pop(s,x); push(s,’s’); while(!stackempty(s)){ pop(s,y);printf(y); }; printf(x); }运行结果是啥（162点数解答 | 2024-12-24 20:43:43）158
- // // main.cpp // step1 // // created by ljpc on 2018/8/31. // copyright © 2018年 ljpc. all rights reserved. // #include <iostream> #include <stack> #include <cstring> #include <algorithm> using namespace std; int main(int argc, const char * argv[]) { // 请在这里补充代码，完成本关任务 /********* begin *********/ stack<char> s1; stack<char> s2; char s[200]; fgets(s,200,stdin); int len=strlen(s); if(s[len-1]=='\n'){ s[len-1]='\0'; len--; } char（518点数解答 | 2024-10-25 17:28:04）158
- 运行不了，修改以下代码写出完整代码#include <windows.h> #include <vector> #include <ctime> #include <cstdlib> const int grid_size = 100; // 每个格子的大小 const int box_count = 3; // 箱子数量 const int target_count = 3; // 目标点数量 const int obstacle_count = 5; // 障碍物数量 struct point { int x, y; }; hbitmap hboxbitmap; // 箱子图片的位图句柄 hbrush htargetbrush; // 目标点的画刷 hbrush hobstaclebrush; // 障碍物的画刷 std::vector<point> boxes; // 箱子的位置 std::vector<point> targets; // 目标点的位置 std::vector<point> o（2686点数解答 | 2024-10-31 15:01:39）278
- 快速排序：# include< iostream>using namespace std;# include< stdlib. h># include< time. h>const int n =10;const int min= 10;const int max=99;int getrand( int min, int max){return ( rand()%( max-min+1)+ min);}void set( int r[], int n){int i;for(i=0;i<n;i++)r[i]=getrand(min, max);}void show( int r[], int n){int i;for(i=0;i<n;i++)cout << r[i]<<" ";cout << endl;}int partition( int r[], int i, int j){//由你完成}void quicksort( int r[], int i, int j){//由你完成}int main(){srand( time(0));int a[n];set(a, n);cout<<"（710点数解答 | 2024-11-14 10:44:25）225
- 快速排序：# include< iostream>using namespace std;# include< stdlib. h># include< time. h>const int n =10;const int min= 10;const int max=99;int getrand( int min, int max){return ( rand()%( max-min+1)+ min);}void set( int r[], int n){int i;for(i=0;i<n;i++)r[i]=getrand(min, max);}void show( int r[], int n){int i;for(i=0;i<n;i++)cout << r[i]<<" ";cout << endl;}int partition( int r[], int i, int j){//由你完成}void quicksort( int r[], int i, int j){//由你完成}int main(){srand( time(0));int a[n];set(a, n);cout<<"（951点数解答 | 2024-11-14 10:46:29）213
- 快速排序：# include< iostream>using namespace std;# include< stdlib. h># include< time. h>const int n =10;const int min= 10;const int max=99;int getrand( int min, int max){return ( rand()%( max-min+1)+ min);}void set( int r[], int n){int i;for(i=0;i<n;i++)r[i]=getrand(min, max);}void show( int r[], int n){int i;for(i=0;i<n;i++)cout << r[i]<<" ";cout << endl;}int partition( int r[], int i, int j){//由你完成}void quicksort( int r[], int i, int j){//由你完成}int main(){srand( time(0));int a[n];set(a, n);cout<<"（472点数解答 | 2024-11-14 10:51:44）200
- #include<iostream> #include<string> #include<iomanip> #include<fstream> #include<stdlib.h> using namespace std; #define ok 1 #define error 0 #define overflow -2 typedef int status; //status 是函数返回值类型，其值是函数结果状态代码。 typedef int elemtype; //elemtype 为可定义的数据类型，此设为int类型 struct book { string id;//isbn string name;//书名 double price;//定价 }; typedef struct lnode { book data; //结点的数据域 struct lnode *next; //结点的指针域 } lnode, *linklist; //linklist为指向结构体lnode的指针类型 string head_1, head_2, head_3; int lengt（35点数解答 | 2024-10-31 17:38:15）175
- #include<iostream> using namespace std;#include<stdlib.h>#include<time.h> const int n =10; const int min =10; const int max =99; int getrand(int min, int max) { return (rand() % (max - min +1) + min); void set(int r[], int n){ int i; for(i = 0; i< n; i++) r[i] = getrand(min,max); void show(int r[], int n) { int i; for (i = 0; i<n;i++) cout << r[i] << ""; cout << endl;}void sift(int r[],int m,int k){ } void heapsort(intr[], int n){ //由你完成 int main(){ srand(time(0)); int a[n]; set(a,n); cout <<"原序（417点数解答 | 2024-11-28 11:20:23）267
- #include <iostream> #include <vector> #include <algorithm> #include <qcoreapplication> int main(int argc, char *argv[]) { qcoreapplication a(argc, argv); int minsize, maxsize, n; std::cin >> minsize >> maxsize; std::cin >> n; std::vector<int> fishsize(n); for (int i = 0; i < n; ++i) { std::cin >> fishsize[i]; } std::sort(fishsize.begin(), fishsize.end()); int safecount = 0; for (int size = minsize; size <= maxsize; ++size) { bool issaf（123点数解答 | 2024-12-01 23:56:16）157