下面程序段的功能是:输出3位至6位正整数中所有的向下斜坡数,比如:21、531、8643、97653......而622、222、3321、9554、92863、66654等都不是。 int i;//要判断的数(循环变量) int n;//要判断的数(每次会变短) int g2, g1;//个位上的数字(新/旧) boolean bz;//标志:true表示是向上斜坡数,false表示非向上斜坡数 for (i = 100; i <= 999999; i++) { 【空挡1】 for (g1 = 10, n = i; 【空挡2】; n = n / 10) { 【空挡3】 if (【空挡4】) { bz = false; break; } 【空挡5】 } if (bz) { system.out.print(i + " "); } }


以下是对空挡的填充建议: 空挡 1:bz = true; 空挡 2:n > 0 空挡 3:g2 = g1; g1 = n % 10; 空挡 4:g1 >= g2 空挡 5:g2 = g1; 以下是三个改进建议: 1. 为代码添加必要的注释,以增强可读性。 2. 将一些复杂的表达式提取为单独的方法,提高代码的可维护性。 3. 考虑使用更具描述性的变量名,使代码更易于理解。 [2024-12-25 15:37:17 | AI写代码神器 | 136点数解答]
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