def read_tdx_trader_stock(self,path=r'c:\new_tdx\t0002\blocknew\buy.blk'): ''' 读取通达信板块自选股交易 ''' try: stock_list=[] with open(r'{}'.format(path),'r+') as f: com=f.readlines() for i in com: i=i.strip() if len(str(i))>0: stock_list.append(i) df=pd.dataframe() df['证券代码']=stock_list df['证券代码']=df['证券代码'].apply(lambda x:str(x)[-


以下是为您补充的 3 点额外需要注意的逻辑点: 1. 考虑异常处理的完整性,比如文件不存在或无法读取的情况。 2. 对于读取到的数据的格式和内容进行更多的验证和处理,确保数据的准确性和可用性。 3. 优化代码的性能,例如减少不必要的内存占用或提高循环的效率。 [2024-12-07 13:53:04 | AI写代码神器 | 84点数解答]
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- def read_tdx_trader_stock(self,path=r'c:\new_tdx\t0002\blocknew\buy.blk'): ''' 读取通达信板块自选股交易 ''' try: stock_list=[] with open(r'{}'.format(path),'r+') as f: com=f.readlines() for i in com: i=i.strip() if len(str(i))>0: stock_list.append(i) df=pd.dataframe() df['证券代码']=stock_list df['证券代码']=df['证券代码'].apply(lambda x:str(x)[-(84点数解答 | 2024-12-07 13:53:04)162
- def read_tdx_trader_stock(self,path=r'c:\new_tdx\t0002\blocknew\buy.blk'): ''' 读取通达信板块自选股交易 ''' try: stock_list=[] with open(r'{}'.format(path),'r+') as f: com=f.readlines() for i in com: i=i.strip() if len(str(i))>0: stock_list.append(i) df=pd.dataframe() df['证券代码']=stock_list df['证券代码']=df['证券代码'].apply(lambda x:str(x)[-(340点数解答 | 2024-12-07 13:53:39)187
- try: stock_list=[] with open(r'{}'.format(path),'r+') as f: com=f.readlines() for i in com: i=i.strip() if len(str(i))>0: stock_list.append(i) df=pd.dataframe() df['证券代码']=stock_list df['证券代码']=df['证券代码'].apply(lambda x:str(x)[-6:]) return df(294点数解答 | 2024-12-07 13:50:32)134
- # 预处理 def load_and_preprocess(file_path): df = pd.read_excel(file_path, engine='openpyxl') df = df.rename(columns={ '评价内容': 'comment', '星级': 'rating' }) # 删除未评论评价以及评论为空的记录 df = df.remove('此用户没有填写评价。') df = df.remove('此用户未及时填写评价内容') df = df.remove('此用户未填写评价内容') df = df.remove('该用户未评价,系统默认好评') df = df.dropna(subset=['comment']) # 去除非文字字符(保留中文、英文、数字) df['comment'] = df['comment'].apply(lambda x: re.sub(r'[^\w\u4e00-\u9fff]', '', (635点数解答 | 2025-06-25 15:46:50)78
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- 检查代码 #include <ctype.h> #include <string.h> void verse(char* str) { *str = tolower(*str); int lens = strlen(str); printf("字符串长度为:%d\n", lens); for (int i = 0; i < lens / 2; i++) { char temp = str[i]; str[i] = str[lens - 1 - i]; str[lens - 1 - i] = temp; } } int pali(char *str) { int lens=strlen(str); char *reverse[lens+1]; strcpy(reverse, str); verse(reverse); return strcmp(str, reverse)==0; } int main() { char str[101];(655点数解答 | 2024-11-08 21:54:45)189