C语言实现：根据年月日时分秒计算北斗时周数和周内秒数

```c #include <stdio.h> // 定义常量 #define SECONDS_PER_DAY 86400 #define SECONDS_PER_HOUR 3600 #define SECONDS_PER_MINUTE 60 // 函数声明 void calculateBeiDouTime(int year, int month, int day, int hour, int minute, int second, int *weeks, int *weekSeconds); int main() { int year, month, day, hour, minute, second; int weeks, weekSeconds; // 输入年月日时分秒 printf("Enter year, month, day, hour, minute, second: "); scanf("%d %d %d %d %d %d", &year, &month, &day, &hour, &minute, &second); // 计算北斗时周数和周内秒数 calculateBeiDouTime(year, month, day, hour, minute, second, &weeks, &weekSeconds); // 输出结果 printf("Weeks: %d, Week Seconds: %d\n", weeks, weekSeconds); return 0; } void calculateBeiDouTime(int year, int month, int day, int hour, int minute, int second, int *weeks, int *weekSeconds) { // 计算从2006年1月1日到输入日期的总秒数 int days = (year - 2006) * 365 + (year - 2006) / 4 - (year - 2006) / 100 + (year - 2006) / 400; // 简化的闰年计算 for (int i = 1; i < month; i++) { switch (i) { case 1: case 3: case 5: case 7: case 8: case 10: case 12: days += 31; break; case 4: case 6: case 9: case 11: days += 30; break; case 2: if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0) days += 29; // 闰年二月29天 else days += 28; // 非闰年二月28天 } } days += day - 1; // 加上当前月份的天数，减1是因为从1月1日开始算 // 计算总秒数 int totalSeconds = days * SECONDS_PER_DAY + hour * SECONDS_PER_HOUR + minute * SECONDS_PER_MINUTE + second; // 计算周数和周内秒数 *weeks = totalSeconds / SECONDS_PER_DAY / 7; *weekSeconds = totalSeconds % (SECONDS_PER_DAY * 7); } ``` ######[AI写代码神器 | 736点数解答 | 2024-12-03 19:57:45]