多种语言实现银行家算法：判断系统资源分配安全状态并输出安全序列

好的，我将为你提供使用 Python 和 C++ 两种编程语言实现的银行家算法。以下是具体的实现代码： Python 实现 ```python def is_safe(resource, claim, allocation): n = len(allocation) # 进程数量 m = len(resource) # 资源种类数量 # 计算当前可用资源 available = resource[:] for i in range(n): for j in range(m): available[j] -= allocation[i][j] # 初始化工作向量和完成标志 work = available[:] finish = [False] * n safe_sequence = [] while True: found = False for i in range(n): if not finish[i] and all(claim[i][j] <= work[j] for j in range(m)): for j in range(m): work[j] += allocation[i][j] finish[i] = True safe_sequence.append(i) found = True break if not found: break if all(finish): return " ".join(safe_sequence) else: return "false" def main(): resource = list(map(int, input().split())) processes = [] claim = [] allocation = [] for _ in range(4): line = input().split() process_name = line[0] processes.append(process_name) claim.append(list(map(int, line[1:4]))) allocation.append(list(map(int, line[4:7])) result = is_safe(resource, claim, allocation) if result == "false": print(result) else: print(" ".join(processes[i] for i in map(int, result.split()))) if __name__ == "__main__": main() ``` C++ 实现 ```cpp #include <iostream> #include <vector> #include <string> #include <sstream> bool isSafe(const std::vector<int>& resource, const std::vector<std::vector<int>>& claim, const std::vector<std::vector<int>>& allocation, std::vector<std::string>& processes, std::vector<std::string>& safeSequence) { int n = allocation.size(); // 进程数量 int m = resource.size(); // 资源种类数量 // 计算当前可用资源 std::vector<int> available = resource; for (int i = 0; i < n; ++i) { for (int j = 0; j < m; ++j) { available[j] -= allocation[i][j]; } } // 初始化工作向量和完成标志 std::vector<int> work = available; std::vector<bool> finish(n, false); while (true) { bool found = false; for (int i = 0; i < n; ++i) { if (!finish[i]) { bool canAllocate = true; for (int j = 0; j < m; ++j) { if (claim[i][j] > work[j]) { canAllocate = false; break; } } if (canAllocate) { for (int j = 0; j < m; ++j) { work[j] += allocation[i][j]; } finish[i] = true; safeSequence.push_back(processes[i]); found = true; break; } } } if (!found) { break; } } for (bool f : finish) { if (!f) { return false; } } return true; } int main() { std::vector<int> resource(3); for (int i = 0; i < 3; ++i) { std::cin >> resource[i]; } std::vector<std::string> processes; std::vector<std::vector<int>> claim(4, std::vector<int>(3)); std::vector<std::vector<int>> allocation(4, std::vector<int>(3)); for (int i = 0; i < 4; ++i) { std::string processName; std::cin >> processName; processes.push_back(processName); for (int j = 0; j < 3; ++j) { std::cin >> claim[i][j]; } for (int j = 0; j < 3; ++j) { std::cin >> allocation[i][j]; } } std::vector<std::string> safeSequence; if (isSafe(resource, claim, allocation, processes, safeSequence)) { for (const auto& process : safeSequence) { std::cout << process << " "; } std::cout << std::endl; } else { std::cout << "false" << std::endl; } return 0; } ``` 使用说明 1. 输入格式： - 第一行：三个整数，表示a、b、c三类资源的总量。 - 接下来的四行：每行七个数据，前一个是进程名，接下来三个是该进程运行所需的a、b、c三种资源总量claim，最后三个是该进程已经分配得到的a、b、c三种资源量allocation。 2. 输出格式： - 如果当前为不安全状态，则输出`false`。 - 如果当前为安全状态，则输出一个安全序列，进程名之间用空格分隔。 希望这些代码能帮助你解决问题！如果有任何疑问或需要进一步的帮助，请随时告诉我。 ######[AI写代码神器 | 1214点数解答 | 2024-11-18 16:47:35]