C语言实现：根据时间替大笨钟“当当”敲钟！

#include <stdio.h> int main() { int hh, mm; scanf("%d:%d", &hh, &mm); if ((hh >= 0 && hh < 12) || (hh == 12 && mm == 0)) { printf("only %02d:%02d. too early to dang.\n", hh, mm); } else { int dang = hh % 12; if (mm > 0) { dang++; } for (int i = 0; i < dang; i++) { printf("dang"); } printf("\n"); } return 0; } ######[AI写代码神器 | 282点数解答 | 2024-10-31 17:59:44]