C语言实现：根据时间替“大笨钟v”敲钟

```c #include <stdio.h> int main() { int hour, minute; scanf("%d:%d", &hour, &minute); if (hour < 12 || (hour == 12 && minute == 0)) { printf("only %02d:%02d. too early to dang.\n", hour, minute); return 0; } if (hour > 12) { hour -= 12; } for (int i = 0; i < hour; i++) { printf("dang"); } if (minute == 0) { for (int i = 0; i < hour; i++) { printf("dang"); } } else { for (int i = 0; i < hour + 1; i++) { printf("dang"); } } printf("\n"); return 0; } ``` ######[AI写代码神器 | 232点数解答 | 2024-10-30 16:27:38]