C 语言实现：计算“yyyy/mm/dd”日期是该年第几天

以下是用 C 语言解决此问题的代码： ```c #include <stdio.h> int isLeapYear(int year) { if ((year % 4 == 0 && year % 100!= 0) || year % 400 == 0) { return 1; } else { return 0; } } int daysInMonth(int month, int year) { int days; switch (month) { case 1: case 3: case 5: case 7: case 8: case 10: case 12: days = 31; break; case 4: case 6: case 9: case 11: days = 30; break; case 2: if (isLeapYear(year)) { days = 29; } else { days = 28; } break; } return days; } int main() { int year, month, day; scanf("%d/%d/%d", &year, &month, &day); int days = 0; for (int i = 1; i < month; i++) { days += daysInMonth(i, year); } days += day; printf("%d\n", days); return 0; } ``` ######[AI写代码神器 | 356点数解答 | 2024-10-30 16:13:41]