C语言：输入年月日，精准计算该日为本年第几天（含闰年判断）

```c #include <stdio.h> struct Date { int year; int month; int day; }; int isLeapYear(int year) { if ((year % 4 == 0 && year % 100!= 0) || year % 400 == 0) { return 1; } else { return 0; } } int daysInMonth(int month, int isLeap) { int days[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; if (isLeap && month == 2) { return 29; } return days[month - 1]; } int main() { struct Date date; scanf("%d%d%d", &date.year, &date.month, &date.day); int totalDays = 0; int i; for (i = 1; i < date.month; i++) { totalDays += daysInMonth(i, isLeapYear(date.year)); } totalDays += date.day; printf("%d\n", totalDays); return 0; } ``` ######[AI写代码神器 | 311点数解答 | 2024-10-30 00:33:00]