巧用C语言：剖析6位正整数最高最低位及奇偶位求和

#include <stdio.h> int main() { int num, i; int highest, lowest; int odd_sum = 0, even_sum = 0; printf("请输入一个6位的正整数："); scanf("%d", &num); highest = num / 100000; lowest = num % 10; for(i=1; i<=6; i++) { if(i%2 == 0) { even_sum += (num % 10); } else { odd_sum += (num % 10); } num /= 10; } printf("最高位为：%d\n", highest); printf("最低位为：%d\n", lowest); printf("奇数位相加为：%d\n", odd_sum); printf("偶数位相加为：%d\n", even_sum); return 0; } ######[AI写代码神器 | 404点数解答 | 2024-10-28 19:13:16]