C语言：精准求解一元二次方程根，含特殊情况处理

以下是使用 C 语言解决此问题的代码： ```c #include <stdio.h> #include <math.h> int main() { double a, b, c; scanf("%lf %lf %lf", &a, &b, &c); if (a == 0 && b == 0 && c == 0) { printf("zero equation\n"); return 0; } if (a == 0 && b == 0 && c!= 0) { printf("not an equation\n"); return 0; } double delta = b * b - 4 * a * c; if (delta > 0) { double x1 = (-b + sqrt(delta)) / (2 * a); double x2 = (-b - sqrt(delta)) / (2 * a); printf("%.2f\n", x1); printf("%.2f\n", x2); } else if (delta == 0) { double x = -b / (2 * a); printf("%.2f\n", x); } else { double realPart = -b / (2 * a); double imagPart = sqrt(-delta) / (2 * a); printf("%.2f+%.2fi\n", realPart, imagPart); printf("%.2f-%.2fi\n", realPart, imagPart); } return 0; } ``` ######[AI写代码神器 | 345点数解答 | 2024-10-26 22:41:36]