Python 函数：根据输入系数求一元二次方程实根

```python import math def solve_quadratic_equation(a, b, c): discriminant = b2 - 4*a*c if discriminant < 0: print("方程无实根！") else: root1 = (-b + math.sqrt(discriminant)) / (2*a) root2 = (-b - math.sqrt(discriminant)) / (2*a) if root1 == root2: print("方程有两个相等的实根：x=" + str(root1)) else: print("方程有两个不同的实根：x1=" + str(root1) + "，x2=" + str(root2)) a, b, c = map(int, input().split()) solve_quadratic_equation(a, b, c) ``` ######[AI写代码神器 | 191点数解答 | 2024-09-27 23:09:46]