找到力量值刚好能挪动冰箱的最小值

```cpp #include <iostream> #include <vector> #include <algorithm> #include <climits> using namespace std; int main() { int n, k; cin >> n; vector<int> strengths(n); for (int i = 0; i < n; ++i) { cin >> strengths[i]; } cin >> k; int minStrength = INT_MAX; // 初始化最小值 for (int s : strengths) { if (s >= k && s < minStrength) { minStrength = s; } } cout << minStrength << endl; // 题目保证至少有一人能挪动 return 0; } ``` ######[AI问答 | 163点数解答 | 2026-06-06 19:38:33]