使用C++计算连续k个守卫最大危险程度总和

```cpp #include <iostream> using namespace std; int main() { int n, k; cin >> n >> k; int a[100005]; int ans = 0; int current_sum = 0; for (int i = 1; i <= n; i++) { cin >> a[i]; if (i <= k) { current_sum += a[i]; } } ans = current_sum; for (int i = k + 1; i <= n; i++) { current_sum = current_sum - a[i - k] + a[i]; ans = max(ans, current_sum); } cout << ans; return 0; } ``` ######[AI问答 | 205点数解答 | 2026-05-30 19:31:33]