C++ 数字字符乘积转换为字符的简洁实现

```cpp #include <iostream> #include <string> int main() { int n; std::cin >> n; std::cin.ignore(); std::string input; std::getline(std::cin, input); if (input.length() != n) { return 1; } int product = 1; bool hasDigit = false; for (char c : input) { if (std::isdigit(c)) { hasDigit = true; product *= (c - '0'); } } if (!hasDigit) { std::cout << "No digits found." << std::endl; } else { std::cout << static_cast<char>(product) << std::endl; } return 0; } ``` ######[AI问答 | 186点数解答 | 2026-05-29 21:06:11]