核晶数字处理：负数取绝对值，正数四舍五入的C++实现

```cpp #include <iostream> #include <cmath> using namespace std; int main() { int n; cin >> n; for (int i = 0; i < n; i++) { double num; cin >> num; if (num <= 0) { num = abs(num); } else { num = round(num); } if (i > 0) { cout << " "; } cout << static_cast<int>(num); } cout << endl; return 0; } ``` ######[AI问答 | 167点数解答 | 2026-05-17 13:13:39]