C++实现查找每位平方和等于本身的两位数及其总数

```cpp #include <iostream> using namespace std; int main() { int count = 0; // 遍历所有两位数 for (int i = 10; i < 100; i++) { int tens = i / 10; int units = i % 10; if (tens * tens + units * units == i) { count++; } } cout << count << endl; return 0; } ``` ######[AI问答 | 138点数解答 | 2026-04-18 20:17:30]