核晶数字处理：负数取绝对值，正数四舍五入的C++实现

```cpp #include <iostream> #include <cmath> using namespace std; int main() { int n; cin >> n; for (int i = 0; i < n; i++) { double num; cin >> num; if (num <= 0) { cout << abs(num); } else { cout << round(num); } if (i < n - 1) { cout << " "; } } return 0; } ``` ######[AI问答 | 153点数解答 | 2026-03-21 19:59:44]