C++实现跳过含4或4的倍数数字从1数到n

```cpp #include <iostream> using namespace std; // 判断一个数是否是4的倍数或者包含数字4 bool isUnlucky(int num) { if (num % 4 == 0) return true; while (num > 0) { if (num % 10 == 4) return true; num /= 10; } return false; } int main() { int n; cout << "请输入一个正整数n: "; cin >> n; for (int i = 1; i <= n; i++) { if (!isUnlucky(i)) { cout << i << " "; } } cout << endl; return 0; } ``` ######[AI问答 | 204点数解答 | 2026-03-21 19:54:48]