用C++求解地劫手臂结晶能量值极差

```cpp #include <iostream> #include <algorithm> using namespace std; int main() { int n; cin >> n; int energy[100]; for (int i = 0; i < n; i++) { cin >> energy[i]; } int max_val = *max_element(energy, energy + n); int min_val = *min_element(energy, energy + n); int range = max_val - min_val; cout << range << endl; return 0; } ``` ######[AI问答 | 148点数解答 | 2026-03-21 19:46:41]