C++实现统计1到n中数字1出现的个数

```cpp #include <iostream> using namespace std; int countDigitOne(int n) { int count = 0; for (int i = 1; i <= n; i++) { int num = i; while (num > 0) { if (num % 10 == 1) { count++; } num /= 10; } } return count; } int main() { int n; cin >> n; cout << countDigitOne(n) << endl; return 0; } ``` ######[AI问答 | 162点数解答 | 2026-03-14 20:08:06]