C++实现自定义“@”运算计算x@y与x@(x+y)

```cpp #include <iostream> using namespace std; // 定义 @ 运算的函数 int atOperation(int a, int b) { return a * a + b * b - a * b; } int main() { int x, y; cin >> x >> y; // 计算 x@y int result1 = atOperation(x, y); cout << result1 << endl; // 计算 x@(x + y) int result2 = atOperation(x, x + y); cout << result2 << endl; return 0; } ``` ######[AI问答 | 167点数解答 | 2026-03-08 20:25:35]