玄铁迷宫寻大白：凭感应器数字定能量痕迹距离的C++程序揭秘

```cpp #include <iostream> using namespace std; int main() { int x; cin >> x; if (x <= 100) { cout << "0~100" << endl; } else if (x <= 200) { cout << "101~200" << endl; } else { cout << "200+" << endl; } return 0; } ``` ######[AI问答 | 114点数解答 | 2026-01-03 19:14:26]