Python实现：根据输入奇数生成对应“X 字矩阵”

```python # 获取用户输入的矩阵的尺寸N N = int(input()) # 逐行打印矩阵 for i in range(N): for j in range(N): # 判断当前位置是否在对角线上 if i == j or i + j == N - 1: print('+', end='') else: print('-', end='') # 每行结束后换行 print() ``` ######[AI问答 | 101点数解答 | 2026-01-02 19:41:24]