C++实现：根据学业与素质成绩判断N名学生是否“优秀”

```cpp #include <iostream> using namespace std; struct Student { int id; int academic; int quality; double total; }; int main() { int N; cin >> N; Student stu; for (int i = 0; i < N; i++) { cin >> stu.id >> stu.academic >> stu.quality; stu.total = stu.academic * 0.7 + stu.quality * 0.3; if (stu.academic + stu.quality >= 140 && stu.total >= 80) { cout << "Excellent" << endl; } else { cout << "Not excellent" << endl; } } return 0; } ``` ######[AI问答 | 155点数解答 | 2025-12-16 12:25:48]