C++程序：根据能量值输出能量光盾制造结果

```cpp #include <iostream> using namespace std; int main() { int energy; cin >> energy; if (energy > 200) { cout << 2 << endl; } else if (energy >= 101 && energy <= 200) { cout << 1 << endl; } return 0; } ``` ######[AI问答 | 74点数解答 | 2025-12-14 14:10:31]