Python 实现区间 [32,122] ASCII 码字符循环打印，按格式整齐输出！

```python # 初始化计数器 count = 0 # 遍历 ASCII 码值从 32 到 122 for ascii_value in range(32, 123): # 转换为对应的字符 char = chr(ascii_value) # 格式化输出 print(f"{ascii_value:3d}: {char:1s}|", end="") # 计数器加 1 count += 1 # 每 5 个字符换行 if count % 5 == 0: print() ``` ######[AI问答 | 133点数解答 | 2025-12-13 20:05:18]