Python 实现区间 [32,122] ASCII 码字符循环打印，按格式输出！

```python # 初始化计数器 count = 0 # 遍历ASCII码值从32到122 for ascii_code in range(32, 123): # 将ASCII码值转换为对应的字符 char = chr(ascii_code) # 格式化输出，右对齐占3格 output = f"{ascii_code:3d}: {char:1s}|" print(output, end="") # 计数器加1 count = count + 1 # 每打印5个字符，换行 if count % 5 == 0: print() # 如果最后一行不足5个，换行 if count % 5 != 0: print() ``` ######[AI问答 | 169点数解答 | 2025-12-09 20:42:46]