Java开发：代码示例揭秘死锁如何在多线程中“卡死”程序

死锁是多线程编程中常见的问题，它发生在两个或更多的线程互相等待对方释放资源，结果是它们都无限期地等待下去，导致程序无法继续执行。下面是一个简单的Java代码示例，演示了如何创建一个死锁： ```java public class DeadlockExample { public static Object lock1 = new Object(); public static Object lock2 = new Object(); public static void main(String[] args) { Thread thread1 = new Thread(new Runnable() { public void run() { synchronized (lock1) { System.out.println("Thread 1: Holding lock 1..."); try { Thread.sleep(100);} catch (Exception e) {} System.out.println("Thread 1: Waiting for lock 2..."); synchronized (lock2) { System.out.println("Thread 1: Holding lock 1 & 2..."); } } } }); Thread thread2 = new Thread(new Runnable() { public void run() { synchronized (lock2) { System.out.println("Thread 2: Holding lock 2..."); try { Thread.sleep(100);} catch (Exception e) {} System.out.println("Thread 2: Waiting for lock 1..."); synchronized (lock1) { System.out.println("Thread 2: Holding lock 1 & 2..."); } } } }); thread1.start(); thread2.start(); } } ``` 在这个例子中，线程1首先获取到锁1，同时线程2获取到锁2。然后，线程1试图获取锁2，线程2试图获取锁1。因为这两个锁都已经被另一个线程持有，所以线程1和线程2都会无限期地等待，从而产生死锁。 ######[AI百度知道回答 | 445点数解答 | 2023-11-09 17:21:55]