在java开发中,简述hashmap的扩容问题new hashmap(19)它的长度是多少 ?


在Java中,HashMap的扩容机制是基于其内部数组的长度。当HashMap中的元素数量达到其内部数组长度的80%时,它将会进行扩容。扩容时,HashMap会创建一个新的内部数组,其长度是原数组长度的两倍,并将所有元素重新散列到新的数组中。 当你创建一个新的HashMap时,如果你指定了其初始容量(例如,new HashMap(19)),那么它的内部数组长度将是你指定的容量。在这个例子中,HashMap的内部数组长度将是19。 HashMap的实际大小(即它包含的键值对的数量)可以超过其容量。在任何时候,如果HashMap中的元素数量超过了其容量,它将会进行扩容。虽然你可以通过指定初始容量来影响HashMap内部数组的初始大小,但这并不能限制HashMap可以容纳的元素数量。 [2023-11-09 16:39:50 | AI小红书种草文 | 190点数解答]
相关提问
- import javax.swing.*; import java.awt.*; import java.awt.datatransfer.clipboard; import java.awt.datatransfer.stringselection; import java.awt.datatransfer.transferable; import java.awt.event.*; import java.io.*; import java.nio.file.files; import java.nio.file.path; import java.nio.file.paths; import java.time.localdatetime; import java.util.hashmap; import java.util.list; import java.util.map; import java.util.random; public class copy { static private final jtextarea textarea = new jtext(1497点数解答 | 2024-08-25 09:40:33)325
- dm.jdbc.driver.dmexception: 数据溢出 at dm.jdbc.driver.dberror.throwexception(dberror.java:636) at dm.jdbc.c.b.p.s(msg.java:225) at dm.jdbc.c.b.p.p(msg.java:185) at dm.jdbc.c.b.p.o(msg.java:166) at dm.jdbc.c.a.a(dbaccess.java:776) at dm.jdbc.c.a.a(dbaccess.java:327) at dm.jdbc.c.a.a(dbaccess.java:435) at dm.jdbc.driver.dmdbpreparedstatement.executeinner(dmdbpreparedstatement.java:284) at dm.jdbc.driver.dmdbpreparedstatement.do_executequery(dmdbpreparedstatement.java:383) at dm.jdbc.driver.(598点数解答 | 2024-10-15 15:48:38)227
- 问题排查:dm.jdbc.driver.dmexception: 数据溢出 at dm.jdbc.driver.dberror.throwexception(dberror.java:636) at dm.jdbc.c.b.p.s(msg.java:225) at dm.jdbc.c.b.p.p(msg.java:185) at dm.jdbc.c.b.p.o(msg.java:166) at dm.jdbc.c.a.a(dbaccess.java:776) at dm.jdbc.c.a.a(dbaccess.java:327) at dm.jdbc.c.a.a(dbaccess.java:435) at dm.jdbc.driver.dmdbpreparedstatement.executeinner(dmdbpreparedstatement.java:284) at dm.jdbc.driver.dmdbpreparedstatement.do_executequery(dmdbpreparedstatement.java:383) at dm.jdbc.dr(403点数解答 | 2024-10-15 15:48:41)920
- import com.opencsv.csvreader; import com.opencsv.exceptions.csvvalidationexception; import java.io.filereader; import java.io.ioexception; import java.text.parseexception; import java.text.simpledateformat; import java.util.*; public class stockstatistics { public static void main(string[] args) { string filepath = "stocks.csv"; // 请确保csv文件与此java文件在同一目录下,或提供完整路径 simpledateformat sdf = new simpledateformat("yyyy-mm-dd"); map<string, stockdata> monthlydata = new has(66点数解答 | 2024-11-13 15:31:04)193
- 详细解释下面的代码: // netty基本操作,两个线程组 bossGroup = new NioEventLoopGroup(); workerGroup = new NioEventLoopGroup(Runtime.getRuntime().availableProcessors() * 2); try { // netty的启动类 ServerBootstrap b = new ServerBootstrap(); b.group(bossGroup, workerGroup) .channel(NioServerSocketChannel.class) .handler(new LoggingHandler(LogLevel.INFO)) //记录日志的handler,netty自带的 .childHandler(new HelloServerInitializer()) .option(ChannelOption.SO_BACKLOG, 2048). childOption(ChannelOption.SO_KEE(244点数解答 | 2025-01-17 18:26:07)148
- function optimalCuttingPlan() % 最优切割方案计算函数(已测试通过) % 作者:数学建模助手 % 最后修改:2023-10-15 %% 数据准备(使用硬编码数据避免文件读取问题) % 原材料数据 [ID, 长度, 缺陷位置, 缺陷长度, 单价] raw_data = [ 1 5.5 1 0.3 17 1 5.5 3 0.2 17.33 2 6.2 2 0.4 20.59 3 7 1.5 0.2 24.41 3 7 4 0.3 24.05 4 5.8 1.2 0.5 17.33 5 6.5 2.3 0.3 22 6 7.5 1 0.6 24.77 7 6 2.8 0.4 19.83 8 8.2 1.3 0.5 27.64 9 6.8 2.1 0.3 23.32 9 6.8 5 0.2 23.69 10 5.6 1.1 0.2 17.66 11 7.3 3.1 0.4 24.77 12 6.1 1.7 0.5 19.83 13 8 2.5 0.3 27.64 14 5.9 3 0.4 18 15 6.3 1.9 0.3 21.27 16 7.8 1.2 0.(3226点数解答 | 2025-06-18 20:59:55)105
- void createlist(listnode* &phead) { phead - new listnode(0): listnodc*p= phcad; for (inti-1;i<10;i++){ listnode*ptmp= new listnode(i); p->next-ptmp; p-ptmp; 创建循环链表 void createlooplist(listnode*&phead) phead-new listnode(0); listnode*p=phead: int length-10; listnode* loopstart-null: for (int i=1: i <length:i++) { listnode *ptmp-new listnode(i): p->next-ptmp; p-ptmp. it (i6i loopstart=ptmp; p->next-loopstart; int lengthofcop(listnode*phead /todo:实现此函数,返回环形链表的环的长度,如果静表无环,返回0 return 0; intmaino t l(193点数解答 | 2024-10-09 16:49:52)168
- void createlist(listnode* &phead) { phead - new listnode(0): listnodc*p= phcad; for (inti-1;i<10;i++){ listnode*ptmp= new listnode(i); p->next-ptmp; p-ptmp; 创建循环链表 void createlooplist(listnode*&phead) phead-new listnode(0); listnode*p=phead: int length-10; listnode* loopstart-null: for (int i=1: i <length:i++) { listnode *ptmp-new listnode(i): p->next-ptmp; p-ptmp. it (i6i loopstart=ptmp; p->next-loopstart; int lengthofcop(listnode*phead /todo:实现此函数,返回环形链表的环的长度,如果静表无环,返回0 return 0; 确定环的起始位置 int(519点数解答 | 2024-10-09 17:31:13)191
- void createlist(listnode* &phead) { phead - new listnode(0): listnodc*p= phcad; for (inti-1;i<10;i++){ listnode*ptmp= new listnode(i); p->next-ptmp; p-ptmp; 创建循环链表 void createlooplist(listnode*&phead) phead-new listnode(0); listnode*p=phead: int length-10; listnode* loopstart-null: for (int i=1: i <length:i++) { listnode *ptmp-new listnode(i): p->next-ptmp; p-ptmp. it (i6i loopstart=ptmp; p->next-loopstart; 实现此函数,返回环形链表的起始位置(438点数解答 | 2024-10-09 17:37:28)196
- using system; using system.collections.generic; using system.linq; using system.text; using system.threading.tasks; namespace teachingmanagementsystem { class program { static void main(string[] args) { console.writeline("欢迎使用简易教学管理系统"); // 创建课程列表 list<course> courses = new list<course> { new course("数学"), new course("英语"), new course("物理") }; // 创建学生(419点数解答 | 2024-10-24 17:49:32)172
- public LineInfo selLineInfo(LineInfo lineInfo) throws Exception { LineBasicInfo lineBasicInfo = new LineBasicInfo(); Date nowTime = new Date(); SimpleDateFormat simpleFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); LineInfo lineInfo2 = new LineInfo(); if (lineInfo.getId() == 0) { lineBasicInfo.setLineName("M1"); lineInfo2.setLineName("**T2_M1"); } else if (lineInfo.getId() == 1) { lineBasicInfo.setLineName((1080点数解答 | 2025-03-04 15:24:59)118
- public LineInfo selLineInfo(LineInfo lineInfo) throws Exception { LineBasicInfo lineBasicInfo = new LineBasicInfo(); Date nowTime = new Date(); SimpleDateFormat simpleFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); LineInfo lineInfo2 = new LineInfo(); if (lineInfo.getId() == 0) { lineBasicInfo.setLineName("M1"); lineInfo2.setLineName("**T2_M1"); } else if (lineInfo.getId() == 1) { lineBasicInfo.setLineName((1080点数解答 | 2025-03-04 15:27:11)138