Python 求 1 到 n 立方和：代码漏洞与正确解法揭秘

```python def sum_of_cubes(n): sum = 0 for i in range(1, n+1): sum += i3 return sum n = int(input("请输入一个整数: ")) result = sum_of_cubes(n) print(f"1到{n}每个数的立方和为: {result}") ``` ######[AI写代码神器 | 93点数解答 | 2024-12-15 16:25:14]