DevC++ 实现：计算并输出 n×n 矩阵边界元素之和

```c++ #include <iostream> using namespace std; int main() { int n; cout << "请输入n的值（n小于等于10）："; cin >> n; int matrix[10][10]; cout << "请逐行输入矩阵元素：" << endl; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { cin >> matrix[i][j]; } } int sum = 0; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { if (i == 0 || i == n-1 || j == 0 || j == n-1) { sum += matrix[i][j]; } } } cout << "边界元素的和为：" << sum << endl; return 0; } ``` ######[AI写代码神器 | 410点数解答 | 2024-11-21 00:19:17]