Python 实现：计算用户输入 n x n 矩阵边界元素之和

```python n = int(input("请输入 n 的值：")) # 定义 n x n 的二维数组 matrix = [[0]*n for _ in range(n)] # 用户输入矩阵元素 for i in range(n): for j in range(n): matrix[i][j] = int(input(f"请输入第 {i+1} 行，第 {j+1} 列的元素：")) # 计算边界元素的和 boundary_sum = 0 for i in range(n): for j in range(n): if i == 0 or i == n-1 or j == 0 or j == n-1: boundary_sum += matrix[i][j] # 输出结果 print("边界元素的和为：", boundary_sum) ``` ######[AI写代码神器 | 319点数解答 | 2024-11-21 00:16:05]