def is_safe_state(resource, claim, allocation): # 资源种类 num_resources = len(resource) num_processes = len(claim) # 可用资源 = 总资源 - 已分配资源 available = [resource[i] - sum(allocation[j][i] for j in range(num_processes)) for i in range(num_resources)] # 计算需求矩阵 need = [[claim[i][j] - allocation[i][j] for j in range(num_resources)] for i in range(num_processes)] # 安全序列 safe_sequence = [] finish = [false] * num_processes # 标记进程是否完成 while len(s
以下是为您补充完整的银行家算法判断系统是否处于安全状态的函数示例代码： ```python def is_safe_state(resource, claim, allocation): # 资源种类 num_resources = len(resource) num_processes = len(claim) # 可用资源 = 总资源 - 已分配资源 available = [resource[i] - sum(allocation[j][i] for j in range(num_processes)) for i in range(num_resources)] # 计算需求矩阵 need = [[claim[i][j] - allocation[i][j] for j in range(num_resources)] for i in range(num_processes)] # 安全序列 safe_sequence = [] finish = [False] * num_processes # 标记进程是否完成 while len(safe_sequence) < num_processes: found = False for i in range(num_processes): if not finish[i] and all(need[i][j] <= available[j] for j in range(num_resources)): available = [available[j] + allocation[i][j] for j in range(num_resources)] finish[i] = True safe_sequence.append(i) found = True if not found: return False return True ``` 在上述代码中，通过遍历进程，判断未完成的进程的需求是否小于可用资源。如果满足条件，则将该进程的已分配资源释放到可用资源中，标记该进程完成，并将其加入安全序列。如果找不到满足条件的进程，则系统处于不安全状态；否则，最终能得到完整的安全序列，系统处于安全状态。 [2024-11-07 17:23:02 | AI写代码神器 | 367点数解答]
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