#define _crt_secure_no_warnings #include <stdio.h> #include <stdlib.h> #include<time.h> int game(char result) { int rn, num; int count = 1; srand((unsigned int)time(null)); for (int i = 0; i < 1000; i++) { rn = rand()%100+1; } for (int i = 0; i < 7; i++) { printf("请输入猜的数"); scanf("%d", &num); if (num == rn) { printf("你赢了,一共猜了%d次", count); i = 7; } else if (num > rn) {


以下是为您补充完整的猜数字游戏代码: ```c #define _crt_secure_no_warnings #include <stdio.h> #include <stdlib.h> #include<time.h> int game(char result) { int rn, num; int count = 1; srand((unsigned int)time(NULL)); for (int i = 0; i < 1000; i++) { rn = rand() % 100 + 1; } for (int i = 0; i < 7; i++) { printf("请输入猜的数"); scanf("%d", &num); if (num == rn) { printf("你赢了,一共猜了%d次", count); i = 7; } else if (num > rn) { printf("猜大了,请重新猜\n"); count++; } else { printf("猜小了,请重新猜\n"); count++; } } if (count > 7) { printf("很遗憾,您没有在 7 次内猜出,答案是 %d", rn); } return 0; } int main() { game(' '); return 0; } ``` 在上述代码中,首先生成一个 1 到 100 之间的随机数,然后让用户进行最多 7 次猜测。每次猜测后会提示猜测结果是大了还是小了,直到猜对或者 7 次猜测用完。 [2024-11-01 12:25:55 | AI写代码神器 | 378点数解答]
- #define _crt_secure_no_warnings #include <stdio.h> #include <stdlib.h> #include<time.h> int game(char result) { int rn, num; int count = 1; srand((unsigned int)time(null)); for (int i = 0;i<1000 ; i++) { rn = rand(); if ((rn <= 100) && (rn >= 1)) { i = 1001; } } for (int i = 0; i < 7; i++) { num = scanf("%d", &num); if (num == rn) { printf("你赢了,一共猜了%d次", count); i = 7; } else if (num > rn) { printf("你猜错了,猜的偏大"); count++; } else if (num < rn) { printf("你猜错了,猜的偏小"); count++; } if (count == 6(403点数解答 | 2024-11-01 12:03:29)229
- #define _crt_secure_no_warnings #include <stdio.h> #include <stdlib.h> #include<time.h> int game(char result) { int rn, num; int count = 1; srand((unsigned int)time(null)); for (int i = 0; i < 1000; i++) { rn = rand()%100+1; } for (int i = 0; i < 7; i++) { printf("请输入猜的数"); scanf("%d", &num); if (num == rn) { printf("你赢了,一共猜了%d次", count); i = 7; } else if (num > rn) {(378点数解答 | 2024-11-01 12:25:55)159
- #include<iostream> #include<complex.h> #include <complex> #include <math.h> using namespace std; #define pi 3.14159265358979323846 int main() { file* stream; stream = fopen("4000-red.raw","rb"); unsigned char* image = (unsigned char*)malloc(4000 * 4000 * sizeof(unsigned char)); fread(image,4000*4000,sizeof(unsigned char),stream); unsigned char* image2 = (unsigned char*)malloc(4000 * 4000 * sizeof(unsigned char)); unsigned char* image3 = (unsigned char*)malloc(4000 * 4000 * sizeof(unsigned(413点数解答 | 2024-11-02 18:16:35)218
- 采用c++语言,实现如下功能: 实现古典密码中的移位密码和仿射密码,具体实现如下接口: c++接口: <<<<<移位密码>>>>> bool is_valid_s(unsinged char k) { 判断k是否为合理的密钥 } int encrypt_s(unsigned char* p, unsigned char k) { 密钥合法则返回1,且密文覆盖明文: 密钥不合法则返回0. } int decrypt_s(unsigned char* c, unsigned char k) { 密钥合法则返回1,且明文覆盖密文: 密钥不合法则返回0. } <<<<<仿射密码>>>>> bool in_valid_a(unsinged char a, unsigned char b) { 判断a,b是否为合理的密钥 } int encrypt_a(unsigned char* p, unsigned char a, unsigned char b) { 密钥合法则返回1,且密文覆盖明文: 密钥不合法则返回0. } int decrypt_a(unsigned char* c, unsign(812点数解答 | 2024-12-18 16:02:36)250
- 把这个代码修改正确#include<reg52.h> sbit key = p3^0; // 按键连接到p3.0 unsigned char code seg_code[] = {0x3f, 0x06, 0x5b, 0x4f, 0x66, 0x6d, 0x7d, 0x07, 0x7f, 0x6f}; // 数码管段码 unsigned char code dash_code = 0x40; // 横杠段码 unsigned int second =0; // 秒表计数 bit running = 0; // 秒表运行状态 void timer0_isr() interrupt 1 { static unsigned int count =0; th0 = (65536 - 1000) / 256; tl0 = (65536 - 1000) %256; count++; if (count >= 1000) { count = 0; if (running) { second++; } } } void delay(unsigned int ms) { unsigned int i(776点数解答 | 2024-10-23 22:51:51)202
- 快速排序:# include< iostream>using namespace std;# include< stdlib. h># include< time. h>const int n =10;const int min= 10;const int max=99;int getrand( int min, int max){return ( rand()%( max-min+1)+ min);}void set( int r[], int n){int i;for(i=0;i<n;i++)r[i]=getrand(min, max);}void show( int r[], int n){int i;for(i=0;i<n;i++)cout << r[i]<<" ";cout << endl;}int partition( int r[], int i, int j){//由你完成}void quicksort( int r[], int i, int j){//由你完成}int main(){srand( time(0));int a[n];set(a, n);cout<<"(710点数解答 | 2024-11-14 10:44:25)225
- 快速排序:# include< iostream>using namespace std;# include< stdlib. h># include< time. h>const int n =10;const int min= 10;const int max=99;int getrand( int min, int max){return ( rand()%( max-min+1)+ min);}void set( int r[], int n){int i;for(i=0;i<n;i++)r[i]=getrand(min, max);}void show( int r[], int n){int i;for(i=0;i<n;i++)cout << r[i]<<" ";cout << endl;}int partition( int r[], int i, int j){//由你完成}void quicksort( int r[], int i, int j){//由你完成}int main(){srand( time(0));int a[n];set(a, n);cout<<"(951点数解答 | 2024-11-14 10:46:29)213
- 快速排序:# include< iostream>using namespace std;# include< stdlib. h># include< time. h>const int n =10;const int min= 10;const int max=99;int getrand( int min, int max){return ( rand()%( max-min+1)+ min);}void set( int r[], int n){int i;for(i=0;i<n;i++)r[i]=getrand(min, max);}void show( int r[], int n){int i;for(i=0;i<n;i++)cout << r[i]<<" ";cout << endl;}int partition( int r[], int i, int j){//由你完成}void quicksort( int r[], int i, int j){//由你完成}int main(){srand( time(0));int a[n];set(a, n);cout<<"(472点数解答 | 2024-11-14 10:51:44)200
- #include<iostream> using namespace std;#include<stdlib.h>#include<time.h> const int n =10; const int min =10; const int max =99; int getrand(int min, int max) { return (rand() % (max - min +1) + min); void set(int r[], int n){ int i; for(i = 0; i< n; i++) r[i] = getrand(min,max); void show(int r[], int n) { int i; for (i = 0; i<n;i++) cout << r[i] << ""; cout << endl;}void sift(int r[],int m,int k){ } void heapsort(intr[], int n){ //由你完成 int main(){ srand(time(0)); int a[n]; set(a,n); cout <<"原序(417点数解答 | 2024-11-28 11:20:23)267
- #include<stdio.h> int copystring(int str1[], int str2[], int n); int main() { int str1[100],str2[100]; int i=0,num,n=0; // 使用 getchar() 来读取字符,检查是否是换行符 while (i < 100) { if (scanf_s("%d", &num) != 1) { while (getchar() != '\n'); break; } str1[i] = num; i++; if (getchar() == '\n') { n = i; break; } } int m = copystring(str1, str2, n); for(i=0;i<m;i++) printf("%d", str2[i]); return 0; } int copystring(int str1[], int str2[], int n) { int j,i; int count = 0; f(392点数解答 | 2024-12-08 15:18:09)166
- void sr(struct student* sr) //输入函数 显示器输入(录入学生信息) { int i = 0; printf("请输入学生的个数:"); scanf("%d", &d); system("cls");//清屏 for (; i < d; i++) { printf("请输入学生的姓名:"); scanf("%s", (*(sr + i)).name); printf("请输入学生的学号:"); scanf("%d", &(*(sr + i)).num); printf("请输入学生的语文成绩:"); scanf("%f", &(*(sr + i)).chinese); printf("请输入学生的数学成绩:"); scanf("%f", &(*(sr + i)).math); printf("请输入学生的英语成绩:"); scanf("%f", &(*(sr + i)).english); printf("请输入学生的计算机成绩:"); scanf("%f", &(*(sr + i)).c(5点数解答 | 2024-07-02 08:40:40)230
- 实现哈希表创建及查找算法,哈希函数使用除余法,用线性探测法处理冲突。 函数接口定义: void createhash(hashtable ht[],int n); //输入不大于m的n个不为0(0表示空值)的数,用线性探查法解决冲突构造散列表 int searchhash(hashtable ht[],int key); //输入一个值key,在散列表中查找key位置 其中 ht 表示哈希表, n表示记录数,key要查找的关键字 裁判测试程序样例: #include<iostream> using namespace std; #define m 16 #define nullkey 0 //单元为空的标记 struct hashtable{ int key; }; void createhash(hashtable ht[],int n); int searchhash(hashtable ht[],int key); int main() { int value,key; int result; int i,j,n; hashtable ht[m]; for(i=0;i<m;i++) ht[i].key=0; cin >> n; if(n>m) return 0; createhash(ht,n); cin >> key; result=searchhash(ht,key); if(result!=-1) cout << "search success,the key is located in "<< result+1; else cout << "search failed"; return 0; } /* 请在这里填写答案 */ 输入样例: 12 19 14 23 1 68 20 84 27 55 11 10 79 55 输出样例: 输出拓扑序列。 search success,the key is located in 6(504点数解答 | 2024-12-21 16:14:58)176